In figure 3.85,
is a parallelogram. It circumscribes the circle with cnetre T. Point E,F, G, H are touching points. If AE = 4.5,EB = 5.5, find AD.

Given: AE = 4.5, EB = 5.5
Here, AE = AH = 4.5 {tangents from same external point are equal}
EB = BF = 5.5{tangents from same external point are equal}
∵ Opposite sides of a parallelogram are equal
∴ AE = DG and EB = GC
Also, DH = DG = 4.5{tangents from same external point are equal}
And FC = GC = 5.5 {tangents from same external point are equal}
⇒ AD = AH + HD = 10
Couldn't generate an explanation.
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