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In a ΔABC, If C is a right angle, then 
We are given that,
∆ABC is a right-angled triangle at C.
Let the sides of the ∆ABC be
AC = b
BC = a
AB = c
By Pythagoras theorem, where C is the right angle,
(AC)2 + (BC)2 = (AB)2
⇒ b2 + a2 = c2
Or,
a2 + b2 = c2 …(i)
Using the property of inverse trigonometry,
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Replacing A by
and B by
,




Substituting the value of a2 + b2 from equation (i),

=tan-1
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