Evaluate each of the following:
The value of sin
is 
∴ The question becomes sin–1
Let sin–1
= y
⇒ –sin y = 
= –sin
As, –sin(θ) is sin(–θ).
⇒ –sin
= sin
The range of principal value of sin–1 is 
and sin 
Therefore, the value of sin–1(sin
) is
.
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