Evaluate each of the following:
The value of cot
is √3.
∴ The question becomes cot–1(√3).
Let cot–1(√3) = y
⇒ cot y = √3
= cot
= √3
The range of principal value of cot–1is (0, π)
and cot
= √3
∴ The principal value of cot–1(cot
) is 
.
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