Write each of the following in the simplest form:

Assume x = sinθ
= sin–1![]()
= sin–1![]()
= sin–1![]()
= sin–1![]()
sin(A+B) = sinAcosB+cosAsinB
∴ The above expression can be written as
= sin–1![]()
= ![]()
But θ = sin–1x
∴ the above expression becomes
sin–1x.
The given equation simplification to
sin–1x.
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