If
,
Then prove that
.
Given:- ![]()
Take
⇒![]()
We know that, Formula
![]()

And
![]()
Thus,
⇒![]()
⇒![]()
⇒![]()
We know that, Formula
![]()
Thus,
⇒![]()
On comparing we get,
⇒![]()
Hence Proved
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