Evaluate each of the following:
As cos(–θ) is cos(θ )
∴ (cos
) = (cos
)
Now,
cos
∴ The question becomes cos–1(
)
Let cos–1
=y
⇒ cos y = 
= cos
The range of principal value of cos–1 is [0,π] and cos 
Therefore, the value of cos–1(cos
) is
.
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