Evaluate each of the following:
As sec(–θ) is sec(θ)
∴ sec
= sec
The value of sec
is 2.
Let sec–1(2) = y
⇒ sec y = 2
⇒ sec(
)
The range of principal value of sec–1is [0, π]–{
}
And sec
= 2
∴ The value of sec–1(sec
) is 
.
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