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4. Inverse Trigonometric Functions
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Q2 of 303 Page 4

Find the set of values of cosec–1(√3/2).

Let y = cosec–1 (√3/2)

We know that,


Domain of y = cosec–1 x is (– ∞, 1] U [1, ∞]


But √3/2 < 1


Therefore, it can not be a value of y.


Hence, Set of values of cosec–1(√3/2) is a null set.


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Questions · 303
4. Inverse Trigonometric Functions
1 1 1 1 1 1 2 2 3 3 3 3 4 5 1 2 3 4 4 4 4 5 5 5 5 1 1 1 1 2 2 3 3 3 1 1 1 1 2 2 3 3 1 1 1 1 1 2 3 3 3 3 1 1 1 1 2 3 3 3 3 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 4 4 4 4 4 4 4 4 5 5 5 5 5 5 6 6 6 6 6 6 7 7 7 7 7 7 7 7 7 7 1 1 1 1 1 1 1 1 1 2 2 2 2 3 4 1 1 1 2 2 2 3 1 1 1 1 1 2 3 4 5 6 7 8 9 10 1 1 1 2 3 3 3 3 3 3 3 3 3 3 4 1 2 2 2 3 3 1 2 3 4 1 1 1 1 2 2 2 2 2 2 2 2 2 2 3 4 4 5 6 7 7 8 8 8 8 8 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
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