Evaluate the following:

Given:- ![]()
Let ![]()
Therefore,
⇒![]()
⇒![]()
Now, by Pythagoras theorem
⇒![]()
⇒![]()
⇒![]()
As given, and putting assume value, we get
![]()
=![]()
We know that: Formula

=![]()
=![]()
=![]()
=
; by rationalisation
= ![]()
= ![]()
Hence
![]()
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