Write the vector equation of the line passing through the point (1, –2, –3) and normal to the plane
.
Equation of the given plane is, ![]()
So, the equation of the vector normal to the plane is given as,
![]()
As the required line should be normal to the given plane, so, the line should be parallel to the normal vector i.e.
.
The line should pass through the point (1, –2, –3).
We can write the position vector of the point as,
![]()
So, the vector equation of the line passing through the point (1, –2, –3) and normal to the plane i.e. parallel to
is given by,
, where
is a scalar(constant).
![]()
Hence, equation of the required line is
where,
is a scalar(constant)
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