Q11 of 230 Page 29

Find the distance of the plane 2x – 3y + 4z – 6 = 0 from the origin.

The given equation of the plane is

2x – 3y + 4z – 6 = 0


Or, 2x – 3y + 4z = 6 …… (i)


Now,


Dividing (i) by , we get


, which is the normal form of the plane (i).


So, the length of the perpendicular from the origin to the plane =


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