Find the vector equation of a plane which is at a distance of 5 units from the origin and which is normal to the vector
.
It is given that the normal vector ![]()
Now, ![]()
The equation of a plane in normal form is
= d (where d is the distance of the plane from the origin)
Substituting
and d = 5.
We get,
= 5
Couldn't generate an explanation.
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