Find the angle between the line
and the plane 10x + 2y – 11z = 3.
Direction ratios of the line
are (2,3,6)
Direction ratio of a line perpendicular to the plane
10x + 2y – 11z = 3 are 10, 2, – 11
As we know that the angle θ between the line
and a plane a2x + b2y + c2z + d2 = 0 is given by

If θ is the angle between the line and the plane, then
∴ ![]()
⇒ ![]()
⇒ ![]()
⇒ sinθ =
⇒ θ = sin – 1(![]()
∴ the angle between the plane and the line is sin – 1(![]()
Couldn't generate an explanation.
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