Find the Cartesian form of the equation of the following planes :

We have,

Now, we know that represents a plane passing through a point having position vector and parallel to the vectors .

Clearly, .

Now, the plane is perpendicular to ,

Hence

We know that vector equation of a plane in scalar product form is given as

Put and in equation (a) we get,

Put

We have,

⇒2y – z = 1

Hence, the required equation of plane is 2y – z = 1