Find the vector and Cartesian forms of the equation of the plane passing through the point (1, 2, – 4) and parallel to the lines
and
Also, find the distance of the point (9, – 8, – 10) from the plane thus obtained.
The plane passes through the point (1,2, – 4)
A vector in a direction perpendicular to
and
is
![]()

Equation of the plane is (![]()
![]()
⇒ ![]()
Substituting
, we get the Cartesian form as
– 9x + 8y – z = 11
The distance of the point (9, – 8, – 10) from the plane
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

