Find the equation of the plane passing through the following points:
(1, 1, 1), (1, – 1, 2) and (– 2, – 2, 2)
If the given points are
then the equation of the plane passing through these three points is given by the following equation.

Now substitute the values given


Now apply the determinant

(x – 1)(– 2 + 3) – (y – 1)(0 + 3) + (z – 1)(0 – 6) = 0
(x – 1)1 – (y – 1)3 + (z – 1)(– 6) = 0
x – 3y – 6z + 8 = 0
this is the equation of plane.
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