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The equation of the plane which cuts equal intercepts of unit length on the coordinate axes is
We know, that the general equation of a plane is given by,
Ax + By + Cz + D=0, where
……… (1)
Here, A, B, C are the coordinates of a normal vector to the plane, while (x, y, z) are the co - ordinates of any point through which the plane passes.
Again, we know the intercept form of plane which is given by,
![]()
Where,
and
and the plane makes intercepts at (a, 0, 0), (0, b, 0) and (0, 0, c) with the x - , y - and z - axes respectively.
Here, a=b=c=1.
Putting, the value of a, b, c in equation (2), we are getting,
![]()
x + y + z=1
Hence, the equation of the plane which cuts equal intercepts of unit length on the coordinate axes is, x + y + z=1.
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