A plane passes through the point (1, -2, 5) and is perpendicular to the line joining the origin to the point
. Find the vector and Cartesian forms of the equation of the plane.
As per the given criteria the required plane is passing through Q (1, -2, 5) and is perpendicular to OP, where point O is the origin and position vector of point P is
. Let the position vector of this point Q be
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And it is also given the plane is normal to the line joining the points O(0,0,0) and position vector of point P is ![]()
Then ![]()
Position vector of
- position vector of ![]()
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We know that vector equation of a plane passing through point
and perpendicular/normal to the vector
is given by
![]()
Substituting the values from eqn(i) and eqn(ii) in the above equation, we get
![]()
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(by multiplying the two vectors using the formula
)
![]()
![]()
is the vector equation of a required plane.
Let ![]()
Then, the above vector equation of the plane becomes,
![]()
Now multiplying the two vectors using the formula
, we get
![]()
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This is the Cartesian form of equation of the required plane.
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