Find the vector equation of the line passing through the point (1, – 1, 2) and perpendicular to the plane 2x – y + 3z – 5 = 0.
Equation of line passing through
and parallel to
is given by
……(1)
Given that the line passes through (1, – 1,2) is
…… (2)
Since , line (1) is perpendicular to the plane 2x – y + 3z – 5 = 0, so normal to plane is parallel to the line.
In vector form,
is parallel to ![]()
So,
as l is any scalar
Thus, the equation of required line,
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