Q2 of 256 Page 7

For what value of x, the matrix is singular?


Hence


=(5-x)×4-(x+1)×2 (Expanding along R1)


|A|=18-6x


For A to be a singular matrix, |A| has to be 0.


Therefore, 18-6x=0 or x=3.


More from this chapter

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33

Mark the correct alternative in the following:

The value of is


 1

If A is a singular matrix, then write the value of |A|.

 3

Write the value of the determinant .

4

State whether the matrix is singular or non-singular.