Q17 of 256 Page 7

Prove the following identities:


Applying R1→R1 + R2 + R3, we get,



Taking, (3a + 2b) common we get,



Applying, C1→C1 – C2 and C3→C3 – C2, we get,




= 3(a + b)b2(3) = 9(a + b) b2


= R.H.S


Hence, proved.


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