Q11 of 256 Page 7

Prove the following identities:


L.H.S =


Apply C1→C1 + C2 + C3



Taking (a + b + c) common from C1 we get,



Applying, R3→R3 – 2R1



= (a + b + c)[(b – c)(a + b – 2c) – (c – a)(c + a – 2b)]


= a3 + b3 + c3 – 3abc


As, L.H.S = R.H.S


Hence, proved.


More from this chapter

All 256 →
9

Evaluate the following:

 10

If ,, then prove that Δ + Δ1 = 0.

 12

Prove the following identities:

 13

Prove the following identities: