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6. Determinants
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Q10 of 256 Page 6

Find the value of x, if


⇒ (x+1)(x+2) – (x–1)(x–3) = 4 × 3 – 1 × (–1)


⇒ (x2 + 2x + x + 2) – (x2 – 3x – x + 3) = 12 + 1


⇒ –2x –1= 13


⇒ –2x = 14


⇒ x = –7


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Questions · 256
6. Determinants
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