If
and
, find |AB|.
Given that
and
, we have to find |AB|
Then,
and ![]()
|A|=1×-1-2×3
=-7 (Expanding along R1)
|B|=1×0-0×-1
=0 (Expanding along R1)
Since |AB|=|A||B|,
Therefore |AB|=-7×0=0
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