Q1 of 256 Page 7

Find the area of the triangle with vertices at the points:

(0, 0) (6, 0) and (4, 3)

Given: – Vertices of the triangle:


(0, 0) (6, 0) and (4, 3)


We know that,


If vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:



Now, substituting given value in above formula



Expanding along R1





= 9 sq.units


Thus area of triangle is 9 sq.units


More from this chapter

All 256 →
1

Find the area of the triangle with vertices at the points:

(2, 7) (1, 1) and (10, 8)

 1

Find the area of the triangle with vertices at the points:

(– 1, – 8), (– 2, – 3) and (3, 2)

 2

Using determinants show that the following points are collinear:

(5, 5), (– 5, 1) and (10, 7)

 2

Using determinants show that the following points are collinear:

(1, – 1), (2, 1) and (4, 5)