Prove the following identities –

Let 
Multiplying a, b and c to R1, R2 and R3, we get


Dividing C1, C2 and C3 with a, b and c, we get

Recall that the value of a determinant remains same if we apply the operation Ri→ Ri + kRj or Ci→ Ci + kCj.
Applying R1→ R1 + R2, we get


Applying R1→ R1 + R3, we get


Taking the term (a – b – c) common from R1, we get

Applying C2→ C2 – C1, we get


Applying C3→ C3 – C1, we get


Expanding the determinant along R1, we have
Δ = (ab + bc + ca)(1)[(ab + bc + ca)(ab + bc + ca)]
∴ Δ = (ab + bc + ca)3
Thus, 
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