Q1 of 256 Page 7

Find the area of the triangle with vertices at the points:

(– 1, – 8), (– 2, – 3) and (3, 2)

Given: – Vertices of the triangle:


(– 1, – 8), (– 2, – 3) and (3, 2)


We know that,


If vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:



Now, substituting given value in above formula



Expanding along R1





sq.units


as area cannot be negative


Therefore, 15 sq.unit is the area


Thus area of triangle is 15 sq.units


More from this chapter

All 256 →
1

Find the area of the triangle with vertices at the points:

(3, 8), (– 4, 2) and (5, – 1)

 1

Find the area of the triangle with vertices at the points:

(2, 7) (1, 1) and (10, 8)

 1

Find the area of the triangle with vertices at the points:

(0, 0) (6, 0) and (4, 3)

 2

Using determinants show that the following points are collinear:

(5, 5), (– 5, 1) and (10, 7)