Q6 of 244 Page 113

Solve each of the following systems of equations by using the method of cross multiplication:
2x + y = 35, 3x + 4y = 65.

We have,

2x + y – 35 = 0 …(i)

3x + 4y – 65 = 0 …(ii)

From equation (i), we get a₁ = 2, b₁ = 1 and c₁ = - 35

And from equation (ii), we get a₂ = 3, b₂ = 4 and c₂ = - 65

Using cross multiplication,

⇒

⇒ and

⇒ x = 15 and y = 5

Thus, x = 15, y = 5

Solve each of the following systems of equations by using the method of cross multiplication:

3x + 2y + 25 = 0, 2x + y + 10 = 0.

Solve each of the following systems of equations by using the method of cross multiplication:

2x + 5y = 1, 2x + 3y = 3

Solve each of the following systems of equations by using the method of cross multiplication:

7x – 2y = 3, 22x – 3y = 16.

Solve each of the following systems of equations by using the method of cross multiplication:

Solve each of the following systems of equations by using the method of cross multiplication:2x + y = 35, 3x + 4y = 65.