Q13 of 244 Page 160

The system x + 2y = 3 and 5x + ky + 7 = 0 has no solution, when

We have,

x + 2y – 3 = 0

And, 5x + ky + 7 = 0

Here, a₁ = 1, b₁ = 2 and c₁ = – 3

a₂ = 5, b₂ = k and c₂ = 7

∴

And,

We know that, for the system having no solution we must have:

∴ k = 10

Hence, option A is correct

The system kx – y = 2 and 6x – 2y = 3 has a unique solution only when

The system x – 2y = 3 and 3x + ky = 1 has a unique solution only when

If the lines given by 3x + 2ky = 2 and 2x + 5y + 1 = 0 are parallel then the value of k is

For what value of k do the equations kx – 2y = 3 and 3x + y = 5 represent two lines intersecting at a unique point?