Q42 of 244 Page 147

Five years hence, a man's age will be three times the age of his son. Five years ago, the man was seven times as old as his son. Find their present ages.

Let the age of the man and his son be x and y years respectively.


According to question -


x + 5 = 3(y + 5)


⇒ x - 3y = 10.....(1)


and,


x - 5 = 7(y - 5)


⇒ x - 7y = - 30.....(2)


Subtracting Equation (2) from (1), we get -


y = 10


Substituting the value of y in equation (1), we get -


x = 40


Thus, Man's age = 40 years


son's age = 10 years


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