Q8 of 244 Page 113

Solve each of the following systems of equations by using the method of cross multiplication:

We have,

…(i)


…(ii)


By simplifying, we get


From equation (i),


⇒ 5x + 2y – 120 = 0 …(iii)


From equation (ii),


⇒ 4x – y – 57 = 0 …(iv)


From equation (iii), we get a1 = 5, b1 = 2 and c1 = - 120


And from equation (ii) we get a2 = 4, b2 = - 1 and c2 = - 57


Using cross multiplication,




⇒


⇒


⇒


⇒ and


⇒ and


⇒ x = 18 and y = 15


Thus, x = 18, y = 15


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