For what value of k does the system of equations
kx + 2y = 5, 3x – 4y = 10
have (i) a unique solution, (ii) no solution?
(i) Given: kx + 2y = 5 – eq 1
3x – 4y = 10 – eq 2
Here,
a1 = k, b1 = 2, c1 = 5
a2 = 3, b2 = - 4, c2 = 10
Given systems of equations has a unique solution
∴
≠ ![]()
≠ ![]()
- 4k
6
k ≠ ![]()
∴ k ≠ ![]()
(ii) Given: kx + 2y = 5 – eq 1
3x – 4y = 10 – eq 2
Here,
a1 = k, b1 = 2, c1 = 5
a2 = 3, b2 = - 4, c2 = 10
Given that systems of equations has no solution
∴
=
![]()
Here,
= ![]()
Here,
- 4k = 6
∴ 
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
