Q11 of 244 Page 160

The system kx – y = 2 and 6x – 2y = 3 has a unique solution only when

We have,

kx – y – 2 = 0 (i)

6x – 2y – 3 = 0 (ii)

Here, a₁ = k, b₁ = – 1 and c₁ = – 2

a₂ = 6, b₂ = – 2 and c₂ = – 3

We know that, for the system having a unique solution it must have:

∴

Hence, option D is correct

If 2^{x + y} = 2^{x – y} = √8 then the value of y is

If and then

The system x – 2y = 3 and 3x + ky = 1 has a unique solution only when

The system x + 2y = 3 and 5x + ky + 7 = 0 has no solution, when