Find the value of k for which each of the following systems of linear equations has an infinite number of solutions:
5x + 2y = 2k,
2(k + 1)x + ky = (3k + 4).
Given: 5x + 2y = 2k – eq 1
2(k + 1)x + ky = (3k + 4) – eq 2
Here,
a1 = 5, b1 = 2, c1 = - 2k
a2 = 2(k + 1) , b2 = k, c2 = - (3k + 4)
Given that system of equations has infinitely many solution
∴
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Here,
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5k = 4×(k + 1)
5k = 4k + 4
5K – 4k = 4
k = 4
∴ k = 4
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