Two cubes each of volume 27 cm3 are joined end to end to form a solid. Find the surface area of the resulting cuboid.
Given: Volume of the cube = 27 cm3
Since volume of cube = (Side)3
∴ (Side)3 = 27cm3
= (3 cm)3
Thus, Side = a = 3 cm
Now, as two cubes are joined from end to end, then
Length of resulting cuboid = l = 2 × 3 = 6 cm
Breadth of resulting cuboid = b = 3 cm
Height of resulting cuboid = h = 3 cm
Surface area of a cuboid = 2 × [lb + bh + hl]
= 2 × [(6 × 3) + (3 × 3) + (3 × 3)]
= 2 × [45]
= 90 cm2
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