Q15 of 55 Page 1

Find the roots of the following quadratic equation: x2 – 3√5x + 10 = 0

Here, on comparing with general equation ax2 + bx + c = 0, we get


a = 1


 


b = - 3√5


 


c = 10


 


Now, Discriminant = D = (b2 – 4ac)


 


D = [45 – (4 × 1 × 10)]


 


= [45 - 40]


 


= 5


 


Therefore roots of the equation are given by:


 


x = (-b ± √D)/2a


 


x = (3√5 ± (√5))/2


 


= [(4√5)/2] or [2√5/2]


 


= 2√5 or √5.


 


Thus the roots of the equation are 2√5 and √5.


 

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