Q27 of 55 Page 1

Find the roots of the equation .


 


The equation is equivalent to:


 


(x - 5) + (2x - 3) = (2x - 3)(x - 5)


 


3x – 8 = 2x2 – 13x + 15


 


2x2 – 16x + 23 = 0


 


Here, on comparing with general equation ax 2 + bx + c = 0, we get


 


a = 2


 


b = - 16


 


c = 23


 


Now, Discriminant = D = (b2 – 4ac)


 


D = [256 - (4 × 2 × 23)]


 


= [256 - 184]


 


= 72


 


Therefore roots of the equation are given by:


 


x = (-b ± √D)/2a


 


x = (16 ± √72))/4


 


= [16 + 6√2)/4] or [16 – 6√2/4]


 


= (8 + 3√2)/2 or (8 – 3√2)/2.


 


Thus the roots of the equation are: (8 + 3√2)/2 and (8 – 3√2)/2.


 

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