Q15 of 55 Page 1

The point A(3, y) is equidistant from the points P(6, 5) and Q(0, -3). Find the value of y.


Since the point A is equidistant from P and Q, therefore,


PA = AQ


Squaring both sides, we get:


(PA)2 = (AQ)2


(3 - 6)2 + (y - 5)2 = (0 - 3)2 + (-3 - y)2


9 + y2 + 25 – 10y = 9 + 9 + y2 + 6y


10y + 6y = 25 – 9


16y = 16


y = 1


Therefore, y = 1


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