Q11 of 49 Page 1

For what values of k, are the roots of the quadratic equation: (k + 4) x2 + (k + 1) x + 1 = 0 equal?

For roots to be equal, discriminant should be zero i.e.,

D = b2 – 4ac


D = (k + 1)2 – 4 (k + 4) (1) = 0


k2 + 2k + 1 – 4k – 16 = 0


k2 – 2k – 15 = 0


[By splitting the middle term]


k2 – 5k + 3k – 15 = 0


k (k – 5) + 3 (k – 5) = 0


(k – 5) (k + 3) = 0


k – 5 = 0 and k + 3 = 0


k = 5 or k = -3


More from this chapter

All 49 →