For what values of k, are the roots of the quadratic equation: (k + 4) x2 + (k + 1) x + 1 = 0 equal?
For roots to be equal, discriminant should be zero i.e.,
D = b2 – 4ac
⸫ D = (k + 1)2 – 4 (k + 4) (1) = 0
⇒ k2 + 2k + 1 – 4k – 16 = 0
⇒ k2 – 2k – 15 = 0
[By splitting the middle term]
⇒ k2 – 5k + 3k – 15 = 0
⇒ k (k – 5) + 3 (k – 5) = 0
⇒ (k – 5) (k + 3) = 0
⇒ k – 5 = 0 and k + 3 = 0
⸫ k = 5 or k = -3
Couldn't generate an explanation.
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