Prove that the points A (2, -1), B (3, 4), C (-2, 3) and D (-3, -2) are the vertices of a rhombus ABCD. Is ABCD a square?

Distance between two points is given by,
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AB = ![]()
BC = ![]()
CD = ![]()
DA = ![]()
⸫ All sides are equal and the angle between the sides is not 90°, hence it’s a rhombus.
⸫ No, it’s not a square because the sides are not perpendicular to each other.
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