A solid cone of base radius 10 cm is cut into two parts through the mid-point of its height, by a plane parallel to its base. Find the ratio in the volumes of the two parts of the cone.

Let the height of the cone be H m
Radius of the frustum = R = 10 cm
After cutting, the new height of the cone =
m
Let the new radius of the cone be r cm
⸫ r =
= 5 cm [⸪ the cut has been made at the midpoint of the cone]
Volume of the new cone =
πr2h
= ![]()
Volume of the frustum = ![]()
= ![]()
= ![]()
= ![]()
⸫ Ratio of the two volumes = ![]()
= 1: 7
Couldn't generate an explanation.
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