Prove that the lengths of tangents drawn from an external point to a circle are equal.

Given: PT and TQ are two tangents from an external point T to a circle
To prove: PT = TQ
In ΔPTO and ΔQTO,
OP = OQ [Radius of the same circle]
∠OPT = ∠OQT = 90° [Tangent to a circle is perpendicular to the radius at the point of contact]
OT = OT [Common]
⸫ ΔPTO ≅ ΔQTO [S.A.S]
⸫ PT = TQ [C.P.C.T.C]
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