Prove that the points A (2, 3), B (-2, 2), C (-1, -2) and D (3, -1) are the vertices of a square ABCD.
Distance between two points is given by,
= ![]()
⸫ AB = ![]()
⸫ BC = ![]()
⸫ CD = ![]()
⸫ DA = ![]()
⸫ AB = BC = CD = DA, all sides are equal
Hence, it’s a square.
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