Q20 of 49 Page 1

Find that value of k for which point (0, 2) is equidistant from two points (3, k) and (k, 5).

Distance between two points is given by,

=


According to question, the points (3, k) and (k, 5) are equidistant from (0, 2), hence


⇒


Squaring both sides, we get


⇒ 9 + k2 – 4k + 4 = k2 + 9


⇒ 4k = 4


⸫ k = 1


More from this chapter

All 49 →
18

The 9th term of an A.P. is equal to 6 times its second term. If its 5th term is 22, find the A.P.

 19

Draw two tangents to a circle of radius 3.5 cm, from a point P at a distance of 6.2 cm from its centre.

 28

Solve for x:

29

The sum of first q terms of an A.P. is 63q – 3q2. If its pth term is -60, find the value of p. Also find the 11th term of this A.P.