Q28 of 49 Page 1

Solve for

Given,

⇒


⇒ (2x + 3) (4 – 3x) = 5x


⇒ 8x + 12 – 6x2 – 9x = 5x


⇒ 6x2 + 6x – 12 = 0


⇒ x2 + x – 2 = 0


⇒ x2 – x + 2x – 2 = 0


⇒ x (x – 1) + 2 (x – 1) = 0


⇒ (x – 1) (x + 2) = 0


⇒ x – 1 = 0 and x + 2 = 0


⸫ x = 1 and x = -2


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