Q27 of 49 Page 1

If the points A (1, -2), B (2, 3), C (-3, 2) and D (-4, -3) are the vertices of parallelogram ABCD, then taking AB as the base, find the height of this parallelogram.


Area of triangle with vertices A (x1, y1), B (x2, y2), C (x3, y3) is given by,


(x1 (y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2))


Area (ΔABD) =


= = 12 sq. units


Now, with AB as the base and h as the height of the ΔABD,


Area (ΔABD) =


Distance between two points is given by,


=


AB =


Area (ΔABD) =


12 =


h =


h = units


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