If the points A (1, -2), B (2, 3), C (-3, 2) and D (-4, -3) are the vertices of parallelogram ABCD, then taking AB as the base, find the height of this parallelogram.

Area of triangle with vertices A (x1, y1), B (x2, y2), C (x3, y3) is given by,
(x1 (y2 – y3) + x2 (y3 – y1) + x3 (y1 – y2))
Area (ΔABD) = ![]()
=
= 12 sq. units
Now, with AB as the base and h as the height of the ΔABD,
Area (ΔABD) = ![]()
Distance between two points is given by,
= ![]()
AB = ![]()
Area (ΔABD) = ![]()
⇒ 12 = ![]()
⇒ h = ![]()
⸫ h =
units
Couldn't generate an explanation.
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