Q17 of 49 Page 1

In Fig. 4, a square OABC is inscribed in a quadrant OPBQ of a circle. If OA = 21 cm, find the area of the shaded region. [Use π = 22/7]

Area of a square OABC = OA2 = 212 = 441 cm2

Length of diagonal of a square = OB = a = = Radius of the quadrant


Area of the quadrant of the circle = πr2 =


= 693 cm2


Area of the shaded region = Area of quadrant OQBP – Area of square OABC


= 693 – 441 = 252 cm2


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