Q17 of 49 Page 1

For what value of k, are the roots of the quadratic equation (k – 12) x2 + 2 (k – 12) x + 2 = 0 equal?

For equal roots, the value of discriminant should be zero i.e.,

D = b2 – 4ac


D = (2k – 24)2 – 4(k – 12) (2) = 0


4k2 – 96k + 576 – 8k + 96 = 0


4k2 – 104k + 672 = 0


k2 – 26k + 168 = 0


k2 – 14k – 12k + 168 = 0


k (k – 14) – 12(k – 14) = 0


(k – 14) (k – 12) = 0


k – 14 = 0 and k – 12 = 0


k = 14 and k = 12


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