In figure 1, common tangents AB and CD to the two circles with centres O1 and O2 intersect at E. Prove that AB = CD.

From the given figure,
AE = CE [Tangents drawn from an external point to the same circle are equal]
EB = ED [Tangents drawn from an external point to the same circle are equal]
⸫ AE + EB = CE + ED
⸫ AB = CD
Hence Proved.
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